a-soccer-ball-at-rest-on-the-ground-is-kicked-with-an-initial-velocity-of-10-ms-at-a-launch-angle-of

Question

A soccer ball, at rest on the ground, is kicked with an initial velocity of 10 m/s at a launch angle of 30°. Calculate its total flight time, assuming that air resistance is negligible.
(A) 0.5 s
(B) 1 s
(C) 2 s
(D) 4 s

Khoobchandra Agrawal · Accepted Answer

Hi, everyone. This is the problem based on projectile motion of a particle in this problem, it is given on the ground Soccer bowl is at rest. It is to be kicked at Anglo production 30 degree with the launch speed off 10 m per second, they have to calculate time taken to land on the ground. That is time off flight as we know that time off flight is to find us to be not sign off it up on G, substituting the value toe. We not extend sign off 30 by 9.8. So it is very close to one second. So be option. It&#x27;s correct, that&#x27;s all. Thanks for watching it.

Ze-Han Lee · Answer

So in this problem we have a soccer ball and initial speed of the SOCO boys. Ah ah! Two meters per second and anglers 30 degrees. So we can find a white component of the initial velocity, which is, uh, Tim. It is the second time sign, 30 degrees rain. So this gives us five meters per second And when the Sobibor hey the ground again the velocity allowing the white direction will be pointing down and had the same magnitude of this a fine meters per second. So the velocity changes Ah ah, Negative five meters per second minus five meters a second. So this is the change of velocity on along the white direction. Right and divide by, uh acceleration on the white direction which is negative g. So this gives us the total time and g here we just take it as a 10 meters per second squared. So the total time is one second

Averell Hause · Answer

We can first say that the horizontal component of the velocity would be equal to initial velocity times Co. Sign of 40 degrees, and this would simply be equal to point 766 times the initial velocity. Now we can say the why components would be the sign of 40 degrees, and this would simply be equal to point 64 three the And so we can say that the horizontal ball horizontal motion the ball covers would be 30 meters in distance in time t. So we can say that about X equals Vico Sign of Fada multiplied by T and so t would be equaling two Delta X over v Co sign of Fada Or we can say doubt tow X, divided by 0.766 V and that would be T. And then it also covers Delta y equaling 2.4 meters. So this would be the sign of fada Times T and then minus 1/2 g t squared. And so we can plug in this t this value of tea into this equation and say that Delta Y is equaling gets a 0.64 three v times Delta X, divided by 0.766 v and then this would be minus G over too, multiplied by Delta X over 0.766 v quantity squared and so solving for V. We can say that then this becomes delta. Why? Which we know to be 2.4 meters equaling. And then again we have 0.643 v multiplied by Delta X, which we know to be 30 meters divided by again 0.766 B minus 4.90 meters per second squared times 30 meters, divided by 300.766 v quantity squared and then you can use your solve function in your tea I 84 85 or 89 in order to solve for the and we see that V, the initial velocity is equaling 18.68 meters per second. This would be our final answer. That is the end of the solution. Thank you for one

Suzanne W. · Answer

A soccer goal is 2.44 m high, So we have y is equal to 2.44 m. A player Kicks role at a distance 10 m. X is equal to 10 m At an angle they did not visible to 25°.. The ball hits the crossbar at the top of the goal. What is the initial speed of the soccer ball? So we can use our equation Y equals tangent data, not times X minus G over two. Maybe not, who sign, state or not, where times X squared. So solve this equation for V, not Plug in our given values, and we get 16.4 meters per second.

Alexander Allen · Answer

Okay, So question 63 is a football. Potter wants to kick the ball so that it is in the air for four seconds and lands 50 meters from where it was kicked. At what angle and with what initial speed should devore Bakhit, assuming that the ball leaves one meter above the ground. So let&#x27;s make a drawing of this. We have some distance that we want to go across on. We&#x27;re starting one meter up on. We traveled in a parabolic projectile path and land on the ground with some initial kick velocity you which is at some angle vita to the horizontal. And for this sort of question, I really like the sea. That method for projectiles we have X and Y&#x27;s are directions just to remind us that why is mescal and exits horizontal? And I, like sue that as a saying, which is just a measure or different relevant quantities in its direction, So s is the distance you travel. Now we know that we want 50 meters in the X direction in the horizontal direction. Andi, In the vertical direction, of course, you still have to descend. That one meter started from one meter up. You are landing on the ground for our insured lost in. But this is the entire question. So we&#x27;re just going to use the idea of some unknown initial velocity. You multiplied by the care of science eater. Because, of course, in the horizontal direction is just the horrors of components that we bought. Of course, that makes you in the vertical direction. The vertical Coke owner, which is you cite, feature in the horizontal direction. There is no acceleration or deceleration. We&#x27;re just ignoring their resistance. So we&#x27;ll take you cost eater here as well and no acceleration. And we know we have to be in the effort four seconds in the Y direction. We&#x27;re unsure about our final velocity, so we&#x27;re just not going away for a second. The acceleration is negative, G just negative because it&#x27;s downwards and G because it&#x27;s the gravitational constant. And, of course, if it was for an ex time wise, it&#x27;s for him like okay, in the X direction. Let&#x27;s formulate an equation which sort of emulate what we&#x27;re looking at here. And that should be that the distance that you travel is equal to the velocity at which you&#x27;re going multiplied by time. And that&#x27;s just because acceleration is so. We can just simplify an equation, too. Distance is equal to the last year I&#x27;ve supplied by type and substituting in some values. We see that 50 which is the distance we want to go through is equal Teoh unknown You co site feature multiplied by four. Now I know we get all of our unknowns onto one site. So 50 divided by four is equal to co sign off eater, right? Let&#x27;s take a look in the Y direction on. This time, our distance in question is a little bit more interesting. The distance that we go through is equal to our initial velocity. Most played by the time that we travel in the direction, plus half multiplied by the acceleration multiplied by time squared, which means that if we want to substitute here, we substitute minus one because we&#x27;re going down one for it is the time multiplied by you sign Peter, and of course, after that we&#x27;re going to take off G over two multiplied by four squared. Now we know that four squared is 16 and we divide that by two as well, so we&#x27;ll simplify this whole later term here, four minus one is equal to for you. Sign Peter and will take off eight G, Meaning to rearrange. We have eight G minus one, divided by four. We&#x27;re taking everything other than yet than the unknowns until one side is equal to you. Sign Feta. And I love this sort of question because we&#x27;re going to take advantage of a couple of nice identities that we know. So this is the first equation, and this is the second we have you co sign Peter and Sigh Cater Sarah. If we just give ourselves a bit more room work down here, let&#x27;s just imagine working out the angle. Well, the angle we can simply take by taking a questions. Let&#x27;s number that one, too, and the Angle theater is worked out simply by dividing equation by equation two. I do apologize. It&#x27;s to buy one, of course, because we got that we want to sign on the top. They re candor of the other way. It just leads to something a little bit different. Let&#x27;s scrap this entirely out. No, it&#x27;s too divided by one that we want here. The reason being is this will give us on the right hand side. You sign feta, divided by you. Co sign feeds up, and they use cancel from both sides. Of course, this is simply equal to on the top. Well, let&#x27;s write it a little bit differently. Nate G. Divided, minus one divided by four. All of that is equal to 50 also divided by four lovely thes divided by force. Cancel. Not that it matters too much. So it&#x27;s eight g, which did not break minus one, divided by 50. And we put this into a calculator and we find that the so I&#x27;m divided by the co sign of theater is 1.548 which is of course, equal to the tangent of Theatre on. We simply put into a calculator for first tangent being the feet er, the angle that we&#x27;re counting the ball that is equal to 57 0.14 Good, Nice start Now how are we going to work out the you if we have a feature where we can, of course, doing some substitutions and get over it? Clever, but why don&#x27;t adjust? Continue down the same park of combining this equations in a different way because we simply know that if we take the equations one anti, square them separately and add them together, we might get an interesting result because, of course, you squared. Co sign squared feature plus U squared sine squared Peter. It&#x27;s simply equal to you. Squared, not supplied by co sign square feet up, plus the signs grant of theater, which is equal to just use Grete. This here is an identity equal to what? So this is going to recover it for us. We simply square both equations one and two, one squared, plus to squared on. What does this give us? Where we know that we&#x27;re going to obtain from this you squared and that is simply equal to eight G minus one course over four square. That, and and to that 50 over four, it&#x27;s just needing that up a bit and square that add them together and take a square bridge. So he is known eight times G eight times, nine for eight. Uh, and that&#x27;s attract one from that. Divide the hotel by four, and after that, the square or 50/4, which allows us to then work out, put into a calculator that are you is simply going to be too 23 meters per second. I trust you guys to work a calculator. At this point, I understand the maths that I&#x27;ve done. So great. This is your answer if you&#x27;re speed at which you kick the ball And here is your answer for the angle at which you need to kick the ball.

Zulfiqar Ali · Answer

only questions for each ball s is equal to its not, ah bliss less be not times D less one divided by two um, times X relation times a T square. Well, four ball A. We have 30 less five T minus one divided by two times nine point age T square. And for do you we have 20 times D minus one divided by two multiply by 9.8 times Are T square Well defined, Uh, the time we have, uh ah. Position off is equal to position of B. So we have QWERTY less. Five D um, minus 4.91 de square is equal to 20. Do you minus, um, four point 91 He square and solving for tea. He is equal to two seconds. Uh, no. Let&#x27;s find out S so it&#x27;s visible to 30 less by multiply by two minus one. Divided by two times nine Going to 81 times two square. So s physical to distance equals 20. Find four meter

Problem

A stone is thrown horizontally with an initial sp…

Problem 8 Easy Difficulty

A soccer ball, at rest on the ground, is kicked with an initial velocity of 10 m/s at a launch angle of 30°. Calculate its total flight time, assuming that air resistance is negligible.
(A) 0.5 s
(B) 1 s
(C) 2 s
(D) 4 s

Answer

B

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