Question
A solenoid has $100 \overline{0}$ turns of wire, is $0.320 \mathrm{~m}$ long, and carries a current of $5.00 \mathrm{~A}$. What is the magnetic field at the center of the solenoid? Assume that its length is long in comparison with its diameter.
Step 1
This can be calculated by dividing the total number of turns (N) by the length (L) of the solenoid. In this case, N is 1000 turns and L is 0.320 m. So, we have: \[ n = \frac{N}{L} = \frac{1000}{0.320} \] Show more…
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A solenoid has 1000 turns of wire, is $0.320 \mathrm{~m}$ long, and carries a current of 5.00 A. What is the magnetic field at the center of the solenoid? Assume that its length is long in comparison with its diameter.
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