Question
A solenoid of length $0.256 \mathrm{~m}$ and radius $2.0 \mathrm{~cm}$ has 244 turns of wire. What is the magnitude of the magnetic field well inside the solenoid when there is a current of $4.5 \mathrm{~A}$ in thewire?
Step 1
First, we need to find the number of turns per unit length (n) of the solenoid. We can do this by dividing the total number of turns (244) by the length of the solenoid (0.256 m): n = 244 turns / 0.256 m = 953.125 turns/m Show more…
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