Question
A solenoid with 25 turns per centimeter carries a current of $25 \mathrm{~mA}$. What is the magnitude of the magnetic field in the interior of the coils?
Step 1
Given that there are 100 centimeters in a meter, we multiply the given number of turns per centimeter by 100. This gives us: \[ N = 25 \, \text{turns/cm} \times 100 \, \text{cm/m} = 2500 \, \text{turns/m} \] Show more…
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