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A solenoid with 475 turns has a length of 6.00 $\mathrm{cm}$ and a cross-sectional area of $2.80 \times 10^{-9} \mathrm{m}^{2} .$ Find (a) the solenoid's inductance and (b) the average emf around the solenoid if the current changes from $+2.00 \mathrm{A}$ to $-2.00 \mathrm{A}$ in $8.33 \times 10^{-3} \mathrm{s}$

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for party of our question were asked to find the induct in CE of the solenoid. Well, the induct in switches l is equal to mu, not which we have written above the magnetic permeability of free space times the number of terms squared, multiplied by the area, divided by the length. No plugging those values into this expression. We find that this is equal to one 0.32 times tended the Vitus 10 and the Newtons here or Henry's eight become box. And it is their solution for a for part B. It asks us to find the average e m f around the soul. Annoyed if the current changes from plus to minus two and 8.33 times 10 to the minus three seconds. Okay, well, the IMF is equal to minus inducted Sze times d ie the change and I over dt the change in t which is time changing current over changing time since his minus induct in CE which we just found, the change in current is minus two amperes minus to reappears. So because he goes from minus 2 to 2 in the time it doesn't end is 8.33 times, 10 to the minus three seconds. Plugging those values into this expression, it comes out to be 6.3 times 10 to the minus eight volts making box, and it is our solution for part B.