A solid aluminum cylinder with $\rho=2700 \mathrm{~kg} / \mathrm{m}^{3}$ has a measured mass of $67 \mathrm{~g}$ in air and $45 \mathrm{~g}$ when immersed in turpentine. Determine the density of turpentine.
The $F_{B}$ acting on the immersed cylinder is
$$F_{B}=(0.067-0.045)(9.81) \mathrm{N}=(0.022)(9.81) \mathrm{N}$$
This is also the weight of the displaced turpentine.
The volume of the cylinder is, from $\rho=m / V$,
$$
V \text { of cylinder }=\frac{m}{\rho}=\frac{0.067 \mathrm{~kg}}{2700 \mathrm{~kg} / \mathrm{m}^{3}}=2.5 \times 10^{-5} \mathrm{~m}^{3}
$$
This is also the volume of the displaced turpentine. We therefore have, for the turpentine,
$$
\rho=\frac{\text { Mass }}{\text { Volume }}=\frac{(\text { Weight }) / g}{\text { Volume }}=\frac{(0.022)(9.81) /(9.81)}{2.48 \times 10^{-5}} \frac{\mathrm{kg}}{\mathrm{m}^{3}}=8.9 \times 10^{2} \mathrm{~kg} / \mathrm{m}^{3}
$$