A solid cylinder of mass $\mathrm{M}$ and radius $\mathrm{R}$ rolls down an inclined plane of height $\mathrm{h}$. The angular velocity of the cylinder when it reaches the bottom of the plane will be.
$\{\mathrm{A}\}(2 / \mathrm{R}) \sqrt{(\mathrm{gh})}$
$\{\mathrm{B}\}(2 / \mathrm{R}) \sqrt{(\mathrm{gh} / 2)}$
$\{\mathrm{C}\}(2 / \mathrm{R}) \sqrt{(\mathrm{gh} / 3)}$
$\{\mathrm{D}\}(1 / 2 \mathrm{R}) \sqrt{(\mathrm{gh})}$