00:01
Okay, so this problem, first of all, let's try to draw this system, because when we have the system well established, everything is going to be easier to see.
00:15
So first of all, we have an insulated, an insulating sphere.
00:22
So let's put here an insulating sphere with radius a.
00:29
So you have an insulated sphere with radius a and charge q.
00:36
That means that the charge is distributed uniform through the entire volume of the sphere.
00:47
Then we have a spherical shell.
00:51
So here we have a spherical shell, concentric spherical shell.
00:57
This is not concentric, but i will try my best to be concentric.
01:01
So this is the concentric spherical shell with a second radius.
01:09
So we have here a radius b.
01:12
And we have the outer spherical concentric shell.
01:18
All this is concentric, okay.
01:20
It's not a good draw, but...
01:24
And this second radius has length c.
01:30
So this is the radius c of the outer shell.
01:33
The inner shell has radiod b and the insulated sphere has charge q and radius a.
01:45
And we finally know and we also know that this shell, this is vertical shell, has a net charge, which means in both sides we have a net charge with negative, negative q.
02:03
Actually, let's put this way.
02:05
We have a q, which is negative 1 microculum.
02:15
Okay, so this is our system.
02:18
We have the insulating sphere inside with charge capital q, and we have this concentric sphertriced spherical shell with our inner radius and an outer radius, which means that this is a capacitor, because we have the inside radius and the outer radius.
02:36
So what we have to do in this problem is to describe a graph of the magnitude of the electric field in this configuration when we go from the radius to 0 to 55 centimeters.
02:53
So we just want to describe the graph, let's put here, of the electric field by the radius.
03:11
Okay? so how are we going to do this? to describe the graph we must know what is the behavior of the electric field and to calculate the behavior of the electric field we must do a gaussian surface in in each one of the regions.
03:33
So we have to make a gaussian surface inside the sphere.
03:38
We have to make a gaussian surface between the insulating surface.
03:43
Sphere and the spherical shell, we have to make a gaussian surface between both of the shells.
03:55
Let's put here.
03:57
And we have to make a gaussian surface outside all of this.
04:02
Okay? so it's kind of polluted the system, but essentially we just need to make a calculation for each one of the regions.
04:14
So, we already make these calculations in previous problems, so let's simplify a little.
04:20
And let's think about the first region.
04:23
In the first region, the first region is when the radius go from zero to a...