Question
A solid sphere has a temperature of $773 \mathrm{K}$. The sphere is melted down and recast into a cube that has the same emissivity and emits the same radiant power as the sphere. What is the cube's temperature?
Step 1
We can write this as: \[ V_{\text{sphere}} = V_{\text{cube}} \] \[ \frac{4}{3}\pi r^3 = l^3 \] Solving for \( l \), we get: \[ l = \left(\frac{4}{3}\pi\right)^{\frac{1}{3}}r \] Show more…
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