Question
A solid sphere is rotating about a diameter at an angular velocity $\mathrm{w}$. if it cools so that its radius reduces to $1 / \mathrm{n}$ of its original value. Its angular velocity becomes$\{\mathrm{A}\}(\omega / \mathrm{n})$$\{\mathrm{B}\}\left(\omega / \mathrm{n}^{2}\right)$$\{C\}$ no$\{\mathrm{D}\} \mathrm{n}^{2} \omega$
Step 1
The moment of inertia of a solid sphere rotating about a diameter is given by $I = \frac{2}{5}mR^{2}$, where $m$ is the mass of the sphere and $R$ is the radius. So, the initial angular momentum is $\frac{2}{5}mR^{2}\omega$. Show more…
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