Question
A solution containing $27.55 \mathrm{mg}$ of an unknown protein per $25.0 \mathrm{~mL}$ solution was found to have an osmotic pressure of 3.22 torr at $25^{\circ} \mathrm{C} .$ What is the molar mass of the protein?
Step 1
We know that $1 \mathrm{~torr} = 1.3158 \times 10^{-3} \mathrm{~atm}$, so the osmotic pressure is $3.22 \mathrm{~torr} \times 1.3158 \times 10^{-3} \mathrm{~atm/torr} = 4.24 \times 10^{-3} \mathrm{~atm}$. Show more…
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A solution containing 27.55 mg of an unknown protein per 25.0 mL solution was found to have an osmotic pressure of 3.22 torr at 25 °C. What is the molar mass of the protein?
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