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A solution contains $1.0 \times 10^{-5}$ mol of KBr and 0.10 mol of $\mathrm{KCl}$ per liter. AgNO $_{3}$ is gradually added to this solution. Which forms first, solid AgBr or solid AgCl?

$5.0 \times 10^{-8} \mathrm{M}$

Chemistry 102

Chapter 15

Equilibria of Other Reaction Classes

Chemical Equilibrium

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University of Toronto

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so there are two reactions. 1st 1 is a G. Sian which this proceeds to Egypt for the day less chlorine negative. And we are already provided with KSB off this reaction, which is 1.8. Multiply 10 days to turn negative. 10. Second reaction is Eiji. So you might on aging or the day of one's being negative. The TSP ran Louis my point, Tzeitel, and this one negative 30. Now we have to solve for the concentration off. Still, Ryan positive in the first and for the second bro mean negative. Using the ke SP formula, ke sp will be equal to the multiplication off concentration off both the product form. So ks before the first case may be Eiji positive multiplied with Clooney Negative. I'm concentration substituting the values a Jeep or the divine Concentration 1.8 multiply 10 days to plan negative 10 divided by 0.10 which gives the concentration for civil war as 1.8 multiply 10 days to one negative nine for the second gaze. Okay, I'm really sorry for both the cases. We have to determine the concentration off Silver Line only for the second case, the brew me nine. Concentration is already provided. So he was in GSP equals concentration off Eiji. Positive multiplied with concentration for grooming. Negative. So K s P will be 5.0. Multiply 10 days to one. Negative 13 equal. Eiji. Positive mind Concentration one plane Siegel. 10 days to plan a negative for you. Finally solving this The concentration for Silver Ryan will be Quintal. Fine. Explain, Tzeitel. 10 days to turn negative. Eight as the concentration for silver. I am a smaller for a G C l. Then ages seal, which means the first reaction will precipitate.

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