Question
A solution is prepared by dissolving 0.67 mol of $\mathrm{MgCl}_{2}$ in $0.50 \mathrm{~kg}$ of water.(a) How many moles of ions are present in solution?(b) What is the change in the boiling point of the aqueous solution?
Step 1
$\mathrm{MgCl}_{2}$ dissociates into $\mathrm{Mg}^{2+}$ and $2\mathrm{Cl}^{-}$ ions in solution. Therefore, for every mole of $\mathrm{MgCl}_{2}$, we get 3 moles of ions. Show more…
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