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A solution is prepared by dissolving 396 g of sucrose $\left(\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}\right)$ in $624 \mathrm{g}$ of water. What is the vapor pressure of this solution at $30^{\circ} \mathrm{C} ?$ (The vapor pressure of water is $31.8 \mathrm{mmHg}$ at $30^{\circ} \mathrm{C}$.)

$$P_{1} \approx 30.8 \mathrm{mmHg}$$

Chemistry 102

Chapter 12

Physical Properties of Solutions

Solutions

Rice University

University of Maryland - University College

University of Toronto

Lectures

03:58

In chemistry, a solution is a homogeneous mixture composed of two or more substances. The term "solution" is also used to refer to the resultant mixture. The solution is usually a fluid. The particles of a solute are dispersed or dissolved in the solvent. The resulting solution is also called the solvent. The solvent is the continuous phase.

05:06

In physics and thermodynamics, the natural tendency of a system to change its state is its tendency to increase the entropy of the system. It is a measure of the disorder in a system.

04:06

A solution is prepared by …

02:47

Calculate the vapor press…

04:02

Calculate the vapor pressu…

12:43

How many grams of sucrose …

01:15

A solution contains 4.5 mo…

03:04

06:33

Consider two solutions, on…

Okay, so in this question, we have to compute the vapor pressure of a solution. To do that, we used Rose low that says that the pressure off some species a gonna be equal the pressure of that species when it's pure. So say the pure solvent times the Moeller ratio off that particular species, the Moeller fraction. So we have the pressure of the water when it's pure 31.8 tour or millimeters of mercury. And we have the masses off both water and sugar so we can compute the moderation. And then we can multiply both to get the vapour pressure off our our solution. So let's go ahead and do that. So let's start by computing the number of moles off the sucrose, which is the sugar zeros Sawyer. And we have 309 6 Gramps. So we used the molar mass to convert that to, uh, most. The molar mass off sucrose is 342 grams, so when you compute them, you will get 1.16 moat. Who now we can go and do the same for water. The number of malls off water. It's going to be equal 624 Gramps, That's ah was given in a question. So we convert that to most, using the more mass again. The Mormons of water is 18 grams. So cancel the units here. Sanity check. And then the value should be 34 0.7. Great. So now we have all the most they are needed so we can compute the total and therefore Dimel aeration. So let's go ahead and compute the Moeller ratio from water. Some alterations symbolized here by X. So that's gonna be the number of most of water. So 34 0.7 mol, divided by the total. So you repeat that 34 0.7 from modern. But you also add the number of malls off the Salyut. Okay, the sugar and that's your more racial. So compute that you should get 96.8. Sorry. 0.968 And, um, this is always gonna be mole ratio has always needs to be below. One cannot be won if it's one you mean is pure is just one thing there. So make sure the a number that you get makes sense came. So that's it. All we need is here, so we go back to Rose formula. And so the pressure of water going to be the pressure when the water is pure, so is 31 point a millimeters of mercury times the molar. Atia. There we go. So you do this little computation here, and you should get 30 0.8 millimeters off mercury. That's your final answer.

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