00:01
Okay, so for this question, they are telling us to solve for the amount of iodine -131 nuclear that will remain undecade after five days.
00:09
So the time is five days, and they tell us the half -life is equal to 8 .07 days.
00:17
So we need two equations in order to solve this question.
00:20
The first one is ln and t, which is the amount of nuclear present after a certain amount of time over and not, which is the initial amount of nuclear present.
00:30
So nt over n knots will be the percentage left after a certain amount of time.
00:36
That is equal to negative k, which is the decay constant times by t, which is the time.
00:42
The next equation is t half -life is equal to 0 .693 over the decay constant k.
00:50
So the first thing we can do is solve for k.
00:54
So we have k times by t of half -life is equal to 0 .693, right? and multiply both sides of this equation by k.
01:04
Now we divide both sides by half -life and we get k is equal to 0 .693 over half -life...