a-sound-wave-travels-through-a-metal-rod-with-wavelength-and-frequency-f-which-of-the-following-is-t

Question

A sound wave travels through a metal rod with wavelength ? and frequency f. Which of the following is true? Select two answers.
(A) When this sound wave passes into air, the frequency will change.
(B) When this sound wave passes into air, the wavelength will change.
(C) While in the metal rod, the ? and frequency f have a direct relationship.
(D) While in the metal rod, the ? and frequency f have an inverse relationship.

Vishal Gupta · Accepted Answer

High in the given problem, using the relation between the speed of the way with its frequency and reverence feasible to F. Lambda as the speed see remains constant, so the frequency and wavelength are inversely related, not directly pens. Here, we can see option C is wrong and he is correct. Further, frequency of wave never changes on changing the medium, so only vigilant may change. Hence Option B is also correct. And finally we can see options B and D are correct here. Thank you.

Ze-Han Lee · Answer

So in this problem we have a matter What? And then we have air on site. So the sound moves from the role to the air. We need to determine which statements, right. So the choice Ace is that the one this sound posses into the air. The frequency we changed. So this is not right. The frequency, we always be the same. It only depends on the source. OK, It does not depend on the material. So it&#x27;s not right. And the bees is that Ah ah. When the sound wave passes into air, the wave lands will change. So this is right because, uh ah f because the frequencies accounted and the relation between the frequency and the wavelength is Lambda equal V over f right? And the V is the velocity of the sun wave. Ah, in such a material. So we see that because the because the velocity of a sound wave in rod in the metal rod and ear, they&#x27;re definitely definitely different. So if after is the same. But if V is different, then the wetlands are different. So Ah, the yeah, so he&#x27;s right. And the choice see, say&#x27;s that Ah ah! Why Oh, in the metal rolled the London The frequency F has a direct relationship, so it just look at this expression. All right, so the wave lands and after they have inverse, inverse relationship well, over half, right? So sees no right saying that. Says he&#x27;s right, Okay.

Ze-Han Lee · Answer

So in this problem we have a son Wave travels from iron wrought into the ear. So, uh, they sound the this the speed of sounding the road is Ah, let&#x27;s see, it&#x27;s V one and the speed in the air is B two and the frequency of the sound. That&#x27;s no change. Even Ah, when the when when comes from the roll into the air So f it&#x27;s ah f f it&#x27;s fixing this in this problem. Ah ah, wait. Glands has expression. Lambda equals V over f right. So as we can see that Ah, if ah if it&#x27;s a constant if these larger than London&#x27;s larger is vey s&#x27;more than love this more right. So, uh, in that case, we&#x27;re going to see that Ah, in the road, the wetlands is lambda equal. I&#x27;m the one who&#x27;ll be one over f in air. Lana, to is be to over half. So because vey wise, larger number two. So I&#x27;m the wives larger than under two, So Okay. Ah, in that sense, we can see that. Ah,

Shoukat Ali · Answer

in this problem. We&#x27;re going to talk about changing the yuan. Quantities went in Greason pitch frequencies directly proportioned to the pitch so it will increase with the increasing peach. The increasing preach increases the frequency which in turns the president over Flint. The speed does not depend upon the beach, so it will remain. Send them. Did you know the wave also does Does not depends upon the beach, so it will also Romantsev.

Salamat Ali · Answer

when light enters from air to the water following property exchange. So the speed off their light to changes and your spirit off light changes frequency demands the same. So the land I should also change. Therefore, option C and D are the right answers.

Sam Limsuwannarot · Answer

to the question here wants us to see which of the statements have been effect about on the frequency. So he here says that heavy, fast moving objects have lower frequencies and light, fast moving objects. So this is first of all, determined By using the de Broglie equation. Lambda is able to age over m times V. So let&#x27;s say we have a heavy object. So the value of M is going to be great and we have a fast a moving object so nonetheless, what this shows is that our value m times visa, our momentum is going to be very high, very great in general. So if we compare that to a lighter one, it&#x27;s going to be basically the effects on the wavelength is that if we have a greater value of the denominator, the wavelength is gonna get, um, in this particular case smaller and smaller. So it is going to have a greater frequency as wavelength is inversely proportional to the frequency. So this one is going to be false. Come be here states that only very light particles could have high frequencies. And generally speaking, this would be true. However, we have to take this into account with velocity. So generally speaking, very light particles are going toe also have very, very high frequency ending velocities. So in this particular case, it is going to make the momentum p here, which is equal to M. Times V is gonna make that value very high. So generally speaking, it&#x27;s going toe make the wave with smaller and smaller. So this would be true. So yes, that&#x27;s true. And see here says, doubling the mass and having its velocity results. No change. That is true this because if you double the mass here, so let&#x27;s say you have to be time is 1/2 feet. Essentially, what you&#x27;re doing is canceling it, so this is going to be true.

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