A spaceship of proper length 300. m takes 0.75 $\mu s$ to pass an Earth observer. Determine the speed of this spaceship as measured by the Earth observer.
well in earth frame of reference Delta T is equal to I'll. Divided by Really on dhe L is the contract ID length envies speed and we know they had contacted land contracted land physical to proper length. Times square root off one minus hui squared, divided by C Square, Dubai, Dubai We now let's bring in the values we have. Delta T Delta T equals zero point 75 multiplied by 10 to the power minus six. Uh is equal to We have proper length. Well, proper land is 300 multiplied by square root off one minus we divided by well, speed of light is three. Multiply by 10 to the power eight. We have square divided by we well, solving for weed We have musical to zero point. It's Seattle Times the speed of light