00:01
The question i was asking us how old would the passenger be as it was measured by the ship's clock? well, we know this kind of question is dealing with the time dilation, which is delta t, equal to gamma times delta t 0.
00:17
Okay? gamma is the lawrence factor, which is equal to 1 over square rule, 1 minus v square, over c square, okay? and since the question was asking us the time measured by the spaceship clock which means it's asking delta t zero and delta t here means the time on the earth okay so we have delta t is equal to uh uh oh it's equal to delta t over gamma okay which is equal to square root 1 minus v square over c squared times delta t okay and we know that v the speed of a spaceship is given as 0 .999c.
01:18
Okay? and delta t is given as, remember, the distance from the spaceship to a point is 710 light years.
01:30
So light years is the distance that light travel in one years.
01:34
So since the 710 light years, that means the time takes the light to travel there is 710.
01:43
Years, okay? and therefore, if we plug in the values, we'll have dota t0 is equal to square root 1 minus 0 .999 c square over c squared, okay, n times the time from a measure from the earth, which is 710 years, okay? and it should give us the delta t0 is about 10 years.
02:28
So remember, the passenger was 20 years old.
02:30
So that means during his trip, eventually he will become 30 years old on a spaceship.
02:39
So it's 20 years plus 10 years, which is 30 years.
02:47
So he'll be 30 years old.
02:50
And for question b was asking us, what will be the year on earth's calendar when the signal was sent back, was sending back to the earth...