00:01
Going to work a problem that uses oms law.
00:05
It says that voltage is equal to current times resistance and also the definition of power.
00:11
It says that current is equal to, i'm sorry, power is equal to current times voltage.
00:15
And so it tells us that there's a 10 -volt element and that the power consumed by it is 2 .5 milliseconds.
00:26
Well, if power is current times voltage, i'm going to find the current that's moving at every point in the circuit and then use that in my other calculations.
00:38
So current is equal to power over voltage, so it is 2 .5 milliseconds divided by a voltage of 10 volts, and so my current is 0 .25 milamms.
00:52
So i'm going to use that and omslaw to find my other unknowns.
01:00
So now if i look, if i need to find v .x, i know that that is equal to the current, moving again through all of the circuit, times the resistance there at x.
01:11
And so i have 0 .25 millamps, and i have a resistance of 10 kilooms.
01:20
And so my voltage there is 2 .5 volts.
01:29
So now i'm able to find the voltage drop from node a to b.
01:34
And notice that my voltage at vx is negative.
01:40
And so the voltage across that resistor is going to be negative as well.
01:46
So you can't have the current or the voltage potential changing...