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A sphere of charge $+Q$ is fixed in position. A smaller sphere of charge $+q$ is placed near the larger sphere and released from rest. The small sphere will move away from the large sphere with (A) decreasing velocity and decreasing acceleration(B) decreasing velocity and increasing acceleration(C) increasing velocity and decreasing acceleration(D) increasing velocity and increasing acceleration

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Chapter 10

Electric Forces and Fields

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October 12, 2020

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question Number five wants us to determine how a small sphere with the charge off, plus Q will move in relation. Thio Larger sphere whose charges plus big Q when it is placed near the larger sphere and let go off now because thes to have, like charges they will repel each other. The acceleration of the small sphere can be determined by this expression here A. The acceleration is equal toe f so e yeah, over em, which can in turn be equated to okay times Charges of these two spheres over mass times are squared. When we moved the small sphere close to the large sphere. As I said, they'll repel each other and small sphere will go off in this direction. And so the distance between them are and will increase. So has our increases. That means the acceleration will decrease. But the force F sub e always has to remain positive. So that means that as Thea sell oration decreases, the velocity must increase as the small sphere gets further away from the big one. Okay? Huh?

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