a-sphere-of-charge-q-is-fixed-in-position-a-smaller-sphere-of-charge-q-is-placed-near-the-larger-sph

Question

A sphere of charge $+Q$ is fixed in position. A smaller sphere of charge $+q$ is placed near the larger sphere and released from rest. The small sphere will move away from the large sphere with 
(A) decreasing velocity and decreasing acceleration
(B) decreasing velocity and increasing acceleration
(C) increasing velocity and decreasing acceleration
(D) increasing velocity and increasing acceleration

Matthew Miranda · Accepted Answer

question Number five wants us to determine how a small sphere with the charge off, plus Q will move in relation. Thio Larger sphere whose charges plus big Q when it is placed near the larger sphere and let go off now because thes to have, like charges they will repel each other. The acceleration of the small sphere can be determined by this expression here A. The acceleration is equal toe f so e yeah, over em, which can in turn be equated to okay times Charges of these two spheres over mass times are squared. When we moved the small sphere close to the large sphere. As I said, they&#x27;ll repel each other and small sphere will go off in this direction. And so the distance between them are and will increase. So has our increases. That means the acceleration will decrease. But the force F sub e always has to remain positive. So that means that as Thea sell oration decreases, the velocity must increase as the small sphere gets further away from the big one. Okay? Huh?

Ze-Han Lee · Answer

So in this problem, we have to pause their charges. And it would release the front rest. Ah, so so the coon force. Between that, we will be putting to this to this two directions, right? And because they&#x27;re trying to push each other way so their separation will becomes larger and larger. And that says the corn force will become smaller. So, uh, next generation, because it is equal force, the love I am and the mess let&#x27;s not change. But the force is decreasing, so acceleration is decreasing. And because the centre region here is always a positive although it is decreasing, it is always positive. So it stays that the velocity here kept increasing. Okay.

Surjit Tewari · Answer

question number 26. When an object is thrown in the upwards direction, then it most to the Magno might and they don&#x27;t stoda ground. The initial velocity is you. This velocity you really degrees are in the maximum height at and becomes zero he had after that it will return towards or is no position and its velocity increases from the maximum height. So the lowest position here velocity is decreasing and here we lost is increasing at the maximum height velocity zero. This is because the ex elation or the object is equal to the acceleration due to gravity G, and this acceleration always points in the downward direction. Vendor object is that&#x27;s its initial position, then acceleration due to gravity is acting on it and it&#x27;s velocities in the poor direction, So the velocity reduces continuously upto the maximum height. At the maximum height, the velocity become zero, but it&#x27;s still acceleration due to gravity is acting on it in the downward direction during its downward motion. The acceleration due to gravity is in the downward direction and its velocity is also in the downward direction. So do do this same directional X elation. The velocity increases in their downward motion so we can see that the acceleration off the object remains the constant and its value is equal to G are nine point. It won me done what a second is squad.

Abhishek Jana · Answer

So when an object is thrown upwards during his entire part of the motion, the ax elation events constant even if, ah, at the maximum height where velocity becomes zero, we still have the X elation with is roughly 10 meters per second squared. So Option E is the correct answer. Thank you.

Athiru Pathiraja · Answer

So to answer this question, we must use confirmation of energy law. So we can said that the Cayenne tick energies equals cooling fly. In this case, so one have over here. Let&#x27;s do the expressions and boo. So one have and B squared is equal to cool as well. Which is take you, who is constant times charged one and charge, too over the rays. And since forgiven all these, uh, constants, we just plug it in. And so for velocity, so one half. So let&#x27;s actually Francis, isolate to the variable. We may not be easier for all of us, So if you don&#x27;t be squared equal tuned tu que que have a second charge over their eighties times its mass. So that&#x27;s an arm. Sorry. Make sure you can differentiate your on TV times its mass. So if you plug in all the valleys to time nine times 10 to the power. Sorry, What&#x27;s cool for the 10 to the power of nine. Can the first charge, which is three. Three my food and yes, which is three Micro Coombs three. Sorry, It&#x27;s actually the first charges that c five. I mean, it doesn&#x27;t really matter which one. We, uh, which charge we take first. But I just like to keep it in order of the question time. This negative nine since its micro Coolum and micro is to the power of negative night tend to the part of negative nine times a second charge, which is positive. Three micro, uh, micro cool. So times three times 10 to the power of negative nine over threes, which is eight centimeters. Yep. So which is airplane? You&#x27;re 8 m and times the the mass, which is just six times 10 to the negative five. Yep. Kg. So six times to the constant. So I&#x27;m just referring back that the question to find out these constants and six cents into the negative five kg it&#x27;s important that we have all these in standard units. So velocity squared. So now we just can compute this on. Actually. Just take the square root of this since we need to do square both sides yet. Hold on. Let me get off this so I can do a proper square with time. Yep. You There is years from now. So now all we need to do is just grab with both sides into the square. So if you swear your port side, we&#x27;re gonna get the answer. I just thought this interact How quickly we&#x27;re going to find out if the velocity is equal to one 1 50 m per second and that&#x27;s it for this one thing.

Caitlin Mccabe · Answer

So for the problem we&#x27;re working with today we have been given a charge of negative three que and we&#x27;re told that has been placed onto a metal sphere solid and has a radius of our. So it looks somewhat like this. And the important thing to take note of with this is that all the charges we have been given are negative, and we know that when we have, like, charges that they will repel against each other. So that means that each of the negative charges were working with are going to want to get as far away from each other as possible. The Olympic force between them will propel the two. And so as such, they will want to move away. However, they still must be contained within the surface of this solid metal sphere. They can&#x27;t simply fly off into the sky or leave from it. And so such in order to maximize their distance, will still staying on this fear. They&#x27;re going to be going towards the surface of the sphere in a formacion that is somewhat like this, where they will be able to maximize the distance between each of these charges while still remaining contained within the body. This fear and so as such, the answer to our question will be see, but the negative three Q will be on the outer surface of the sphere as this is a point at which they will maximize their distance between one another while still being contained.

Problem

An object of charge $+q$ feels an electric force …

Problem 5 Easy Difficulty

Answer

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