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Hello everyone.
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So in this question we will be learning about the basic concept of fluid mechanics.
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The question is a spherical ball of radius r and the electric density 0 .5 is plotting in the equilibrium in water with half of its immersed in water.
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The work done in pushing the ball down so the whole of it is just immersed in water is what we have to find.
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It is given that the density of water is given as low.
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So when when the ball is pushed down, the water gains potential energy, whereas the ball loses potential energy.
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Hence, the gain in the potential energy of the water would be equal to v -r -c multiplied by r c minus v by 2, 3 r by 8c.
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Right? so this is when half of the spherical ball is immersed in the water.
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The rise of the cg, that is center of gravity, of the displaced water, would be 3 r by 8...