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A spinner has 4 sections labeled $A, B, C,$ and $D .$ Can the spinner be designed so $P(A)=\frac{1}{12}, P(B)=\frac{1}{6}, P(C)=\frac{1}{3},$ and $P(D)=\frac{5}{12} ?$ If so, explain how.
since the spinner has 4 sections and from probability law, Spinner has 1 section of $\mathrm{A}, 2$ sectionsof $\mathrm{B}, 4$ sections of $\mathrm{C}$ and 5 sections of $\mathrm{D}$ .Hence spinner design is possible.
Precalculus
Geometry
Intro Stats / AP Statistics
Chapter 12
Probability And Statistics
Section 1
Probability Distributions
Introduction to Combinatorics and Probability
Probability
Graphs and Statistics
Descriptive Statistics
Probability Topics
Piedmont College
University of Michigan - Ann Arbor
Boston College
Utica College
Lectures
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So you want to see if ah, four section spinner could meet each of those probabilities? So you have to do is add up those probabilities. So 1/12 plus 1/6 plus 1/3 plus 5 12 So just using the T I calculator. If you add those up, you get exactly what sense it equals one. Yes, it can be a valid Stenner.
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