A square matrix $A$ of order $n$ is invertible if there is a matrix $B$ such that $A B=I_{n}=B A$ . Then $B$ is the inverse of $A,$ denoted by $A^{-1}$. Verify that $B=A^{-1}$ . Assume that $k=a d-b c \neq 0$ .
$$A=\left[\begin{array}{rrr}{1} & {-2} & {0} \\ {3} & {1} & {-1} \\ {1} & {2} & {-3}\end{array}\right], B=\frac{1}{17}\left[\begin{array}{rrr}{1} & {6} & {-2} \\ {-8} & {3} & {-1} \\ {-5} & {4} & {-7}\end{array}\right]$$