00:01
So a matrix is normal if a to the a is equal to a times a.
00:08
So here we get that a star is the conjugate transpose of a.
00:15
So we compute a star, which is going to be a star is going to be equal to 2, negative i, negative i, 2.
00:27
And then we compute a star times a, and we get that a star times a is equal to 5 .005, and then we compute a times a star, and we get that a times a star, indeed, is also equal to 5505.
00:51
So therefore, yes, we are normal, and then we diagonalize a.
00:57
You find the eigenvalues of a by taking the determinant of a minus lambda i and send it equal to zero.
01:04
So doing so is going to give us 2 minus lambda squared equals negative 1, giving us that 2 minus lambda is plus or minus i.
01:16
So our two eigenvalues, our lambda 1 is 2 minus i, and then lambda 2 would be 2 plus i.
01:24
And then for the corresponding eigenvectors, well for lambda 1, we do a minus lambda 1 times i, times v is equal to 0, and get the eigenvector v1 as the vector 1 negative 1...