00:01
16 .56.
00:03
So we've got a standing wave on a string here.
00:09
The si units are assumed.
00:11
So y, this is in meters, x is in meters.
00:15
This is 5 pi radiance for meter.
00:17
This is 40 pi radiance per second, but we're saving ourselves a little bit of bother with writing all that out.
00:24
And then the parentheses we need to separate the things with units from the symbols, et cetera, and so forth.
00:29
That you just, you know, it's a bit lazy, but sometimes laziness is okay.
00:36
So we want to find the location of the first three nodes, the ones with the smallest three x values for x graded n or equal to zero.
00:48
We want to find the period of the oscillatory motion of any point that isn't a node.
00:56
Obviously, since the nodes don't move, talking about them having a period of oscillation is a little bit.
01:01
Bit meaningless.
01:03
Then we have two traveling waves that interfere to produce the standing waves.
01:10
We want to find their speed and amplitude, and then we want to find the first three times after t equals zero where all points on the string have a zero transverse velocity.
01:33
So we have a number of things to do, but some of them are kind of you do them all at once.
01:41
So we want the nodes are going to be given by sign of 5 pi x equals 0.
01:57
This implies that 5 pi x is equal to 0, pi, 2 pi, etc., which means that x is going to be 0, 1 5th, 2 fifths, 3 5ths, and so on forever.
02:34
Or until you reach the end of the string.
02:41
So then the smallest ones, we can just add an m for meters on here and express them as decimals.
02:47
And so we have one at zero meters, one at 0 .2 meters, and then one at 0 .4 meters.
02:56
And then every 0 .2 meters after that will have another node, but we only care about the ones with the three smallest x values.
03:20
So every point except for the nodes has a simple harmonic motion, with the frequency that's just omega over 2 pi...