00:01
Hi, everybody.
00:01
So for this one, we need find the flow, extra temperature, and the rate change into table a8.
00:09
So we need to find the energy equation.
00:11
And i'm going to first find h1 before i write down the energy equation, okay? so we got 0 .5 times h1 of co2 plus 0 .5 times h1 of h2.
00:31
This is going to give us 0 .5 times 1 -223 .34 plus 0 .5 times 2466 .25.
00:48
And so this is going to have us equal 218444 .795 kilo -kilajoules per kilogram.
01:02
Okay, so now we can write the q value here.
01:06
So it's going to be m, h2 minus h1.
01:10
Okay.
01:12
And now it's going to be qm equals h2 minus h1.
01:19
And now it's just going to be h2 equals h2 minus h1.
01:21
And now it's just going to be h2 equals h1 plus q over m.
01:28
Okay.
01:29
And now it's going to be 1, 8, 4, 4 .795 minus 300 over 0 .3, which equals 844 .795, kilojoules per kilogram.
01:53
Okay.
01:55
And now for trial, air for t of h2.
02:00
So now we have the trial and error for t of of h2 at 500k.
02:18
And we have h2 equals 0 .5 times 401.
02:26
52 plus 0 .5 times 9 at 3 .5.
02:34
Which equals 6 .68 .3 .2 kilojoules per program.
02:42
And now we have it at 550k.
02:50
Make my handwritten, this is a tabby here, do you mean? okay, there we go.
02:55
And the 8 .2 here is going to be 0 .5...