Question
A steel rod of $30 \mathrm{~mm}$ diameter and $0.3 \mathrm{~m}$ long is Subjected to a tensile force $W$ kilo newton acting axially. The temperature of the rod raised through $80^{\circ} \mathrm{C}$ and total extension measured as $0.35 \mathrm{~mm}$. The value of $\mathrm{W}$ is:$\left(Y_{\mathrm{s}}=2 \times 10^{5} \mathrm{~N} / \mathrm{mm}^{2}, \alpha_{5}=12 \times 10^{-6} /{ }^{\circ} \mathrm{C}\right)$(a) $29.20$(b) 40(c) 50(d) 12
Step 1
3 \, \text{m} = 300 \, \text{mm}$, the temperature rise $\Delta T = 80^{\circ}C$, and the total extension $\Delta L = 0.35 \, \text{mm}$. We need to find the tensile force $W$. Show more…
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