00:01
So for this problem, we're given the length, the diameter of the wire, the resistivity, and the potential difference.
00:09
So for part a, we're looking for the electric field.
00:13
So we have the equation, potential difference is equal to the electric field times the distance, which in this case is just the length of the wire.
00:22
So then electric field is equal to potential difference over the length, which in this case is 8.
00:32
Volts over meter.
00:34
And the direction is to the right since the positive charges move from high to low potential and they move with the electric field.
00:41
So in this case that's to the right.
00:44
For part b, we're looking for the resistance.
00:48
And for this, we just need to use the equation.
00:50
Resistance is equal to the resistivity times the length over the area.
00:56
So pi times diameter over two squared.
01:00
And so if we plug in our values for all the those, we find the resistance is equal to .637 oms...