Question
A straight wire of mass $200 \mathrm{gm}$ and length $1.5$ meter carries a current of 2 Amp. It is suspended in mid-air by a uniform horizontal magnetic field B. [take $\left.\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right]$. The $\mathrm{B}$ is(a) $\overline{(2 / 3) \text { tes } 1 a}$(b) $(3 / 2)$ tesla(c) $(20 / 3)$ tesla(d) (3/20) tesla
Step 1
Here, $\theta$ is the angle between the magnetic field and the current, which is 90 degrees in this case. So, $sin\theta = sin90 = 1$. Therefore, the magnetic force $F$ is equal to $BIL$. Show more…
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"A straight wire of mass 200 g and length 1.5 m carries a current of 2A. It is suspended in mid air by a uniform magnetic field B. What is the magnitude of the magnetic field?"
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