A straight wire segment of length 0.60 m carries a current of 18.0 A and is immersed in a unif

step 1 In this question, we have an 18 amp current passing through a 0 .6 metre length of wire. It's im

A straight wire segment of length 0.60 m carries a current...

A straight wire segment of length $0.60 \mathrm{~m}$ carries a current of $18.0 \mathrm{~A}$ and is immersed in a uniform external magnetic field of magnitude $0.20 \mathrm{~T}$. (a) What is the magnitude of the maximum possible magnetic force on the wire segment? (b) Explain why the given information enables you to calculate only the maximum possible force.

Key Concepts

Dependence on the Angle Between the Wire and Magnetic Field

The force experienced by the conductor depends on the sine of the angle (?) between the current's direction and the magnetic field. The maximum force occurs when the wire is perpendicular to the magnetic field (? = 90°), since sin 90° equals one. This dependency is crucial, as without knowing the specific orientation of the wire relative to the magnetic field, one can only calculate the maximum possible force under the assumption that the wire is oriented perpendicularly.

Uniform Magnetic Field

The scenario assumes the magnetic field is uniform, meaning its magnitude and direction remain constant throughout the region where the wire is placed. This ensures that the force calculation using the formula F = I L B sin? is valid along the entire length of the wire, simplifying the analysis and allowing the focus to remain on the orientation factor (sin?) for determining the maximum force.

Magnetic Force on a Current-Carrying Conductor

This concept involves understanding that a current-carrying wire in a magnetic field experiences a force given by the equation F = I L B sin?, where I is the current, L is the length of the wire, B is the magnetic field strength, and ? is the angle between the wire and the field. This formula quantifies how the factors such as current strength, wire length, and magnetic field intensity contribute to the resulting force on the conductor.

Transcript

Please give Ace some feedback