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Numerade Educator

# A street light mounted at the top of a $15-ft-tall$ pole. A man $6 ft$ tall walks away from the pole with a speed of $5 ft/s$ along a straight path. How fast is the tip of his shadow moving when he is $40 ft$ from the pole?(a) What quantities are given in the problem?(b) What is the unknown?(c) Draw a picture of the situation for any time $t.$(d) Write an equation that relates the quantities.(e) Finish solving the problem.

## a) $15 \mathrm{ft}, 6 \mathrm{ft}, \quad 5 \mathrm{ft} / \mathrm{s}, 40 \mathrm{ft}$b) The rate that the tip of the man's shadow is moving when he is 40 ft from the polec) See step for answerd) $\frac{6}{15}$e) $\frac{25}{3} \mathrm{ft} / \mathrm{s}$

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the problem is a streetlight market act to cop off fifteen foot tor poor a man, six foot tor walks away from the pole with speed of our foot from second last street past. How fast is the tip of his shadow moving one. His forty foot's from the pole at a watch. Quantities are given in the problem I had of the light height of a man. Andi Speed. It was a man and the distance of miles from the pole. What if an moment, part B. Speed of the tip of its shadow? Moving. See job picture of the situation. I need to if this is streetlight with fifteen on man. Six. Andi, He This's a distance that is off you and this's a Shino. People settle here how to be right on equation that relates the quantities or part of the So If we didn't know this distance, it's us. Then as minus five t over us is equal to six. Fifteen. Had he finished solving the problem? So from what you have fifteen Nice Linus. Some deep laugh. Yes, he called to six. Some nine us. It's equal to seventy five. Fifty. Us is equal to seventy five over nine times to you. Yes, he it's the cartoon seventy five over nine

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