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A student attaches a 1.5 kg mass to a 40 cm long string. The student then begins to whirl the mass in a horizontal circle with increasing speed. If the string snaps when the mass has a speed of 6 m/s, what is the breaking strength of the string?(A) 60 N(B) 120 N(C) 180 N(D) 240 N

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Chapter 13

Practice Test 3

Section 1

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what, in the given problem, length off the spring is given. S l is equal to 40 centimeter. Or we can say this is 0.40 m moss. A fetched with each is MM is equal to 1.5 kilograms. Mhm. The string snaps when their speed achieved by the mask is 6 m for a second. So the centrifugal force acting on this mask under which the spring will snap that centrifugal force is given by the expression and we squared by our and for our means, the radius of a circle. This is the land of the strength, So plugging in all known values here Mm mass is the 1.5 kg. For we. This is 6 m per second to the square for Lent. This is 0.40 meter. So this force at which the string Biggs comes out Toby 135 Newton. So out off the four options given eight. Option says the breaking strength of the string is 60 Newton BC's. This is 1 20. Newton C. Says this is 1 80 Newton and D. C is this is 240 Newton. But as the string is breaking. Have one. 35 Newton so we can see the breaking strength. Offspring is 120 Newtons. So the answer off the question is option B, which says the breaking strength is 120 Newton. Thank you.

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