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A student launched a small rocket with a mass of 50 kg into the air with an initial velocity of 10 m/s in the positive vertical direction. The student then turns on the secondary engines of the rocket to apply a constant upwards force that increases the velocity of the rocket to 15 m/s. If the force provided by the secondary engines did 2,000 J of work, how much work did the force of gravity do on the rocket?(A) –500 J(B) –750 J(C) –1,250 J(D) –1,500 J

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Chapter 13

Practice Test 3

Section 1

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hi in the given problem mass of the small rocket which is moving vertically upward Is given us 50 kilogram. It's initially speed Is given to be we I is equal to 10 meter per second and finally after operating another engine In this rocket. The finally speed achieved by the rocket is 15 m/s. So this increase in its kinetic energy should be equal to the work done by the second engine over the rocket. But if we consider the energy, if you consider the work done by the gravity on the rocket, so this change in kinetic energy of the rocket will be less than the work done by the engine. So first of all, we find the change in kinetic energy of this rocket so that change in the kinetic energy of the rocket will be given by delta E. K. Is equal to final. Kinetic energy means half M V F square minus initial. Kinetic energy means half mv I square. Or we can say this is half M bracket to be f square minus V. I square plugging in all known values form us. This is 50 kg for we have this is square of 15 m per second and then this is a square off 10 m/s. Here it comes out to be 25. Break 225 0 jews. So finally this change in kinetic energy comes out to be 25, multiplied by 125 jewels means this is 3125 Jews. The actual change in kinetic energy. No, the work done by the engine is given us. W is equal to two 1000 Jews. And here this is some mistake in this medical as work done by the engine should be quite more than the kinetic energy that change in kinetic energy of the rocket. Because here this work done by the engine then will be compensated by the work done by gravity means if we consider work done by the gravity on the rocket to be W. G. Then work done by the engine means this W. And then subtracted by this work done by the gravity. This should be equal to the change in kinetic energy. So if I put the values here here, this work done by the Engine means 2000 minus work done by. The gravity should be equal to 3 25 3125 jewels. Which will give us the work done by the gravity to be equal to 2000 minus 3125. Here It will come out to be -1125 Jews means we've done by the gravity is coming to be negative, but this is impossible and none of the option is matching here. Hands, you can see here. Something is wrong. In this given problem is there is some and in the problem, either in the problem or in the given options, there is some error. Thank you.

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