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A student mixes 100 $\mathrm{mL}$ of 0.20 $\mathrm{M}$ HCl with different volumes of 0.50 $\mathrm{M}$ NaOH. Are the final solutions acidic, basic, or neutral? Explain your thinking.a. 100 $\mathrm{mL}$ of $0.20 \mathrm{M} \mathrm{HCl}+20 \mathrm{mL}$ of 0.50 $\mathrm{M} \mathrm{NaOH}$b. 100 $\mathrm{mL}$ of $0.20 \mathrm{M} \mathrm{HCl}+40 \mathrm{mL}$ of 0.50 $\mathrm{M} \mathrm{NaOH}$c. 100 $\mathrm{mL}$ of $0.20 \mathrm{M} \mathrm{HCl}+60 \mathrm{mL}$ of 0.50 $\mathrm{M} \mathrm{NaOH}$

a.acidicb.neutralc.basic

Chemistry 101

Chapter 16

Acidic Toxins

Section 6

Titration

Intro to Chemistry

Atoms, Molecules and Ions

Carleton College

University of Maryland - University College

Brown University

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question Number five asks you to determine whether or not the final solution is acidic, basic or neutral after mixing certain volumes at particular concentrations of HCL and N a. O. H. To answer this question, you need to figure out how many moles of HCL you have and how many moles of N a. O. H. You have to calculate the moles of HCL that you have. In each case, we're taking 100 mL at 1000.2. Moeller 100 mL is 1000.100 leaders in the concentration of point to Moller. If we take the mole arat e times the volume that will give us malls HCL So we have 0.2 00 moles HCL. We then need to compare the moles of HCL to the moles of O H that we have added. If we have more Mel's Ohh! The solution is basic. If we have an equivalent number of molds of any ohh as HCL, the solution is neutral. And if we have fewer moles of any ohh than HCL than the solution is a city because we have extra acid that was not neutralized by the Ohh that we added So for part A, we add 20 mL, which is 0.20 leaders at a concentration of 0.50 Moeller. So that gives us zero 0.10 malls. Ohh! We compare that to what we have up here. We added fewer moles of N a O. H, which means we have excess hcl, so the solution is acidic. For Part B, we add 40 mil leaders, which is 0.40 leaders at 0.5 Moeller zero 0.50 Moeller That then gives us zero 0.20 malls N a o h. So we have equal moles sodium hydroxide as n a. O. H. The solution has reacted completely with all of the acid. There is nothing in excess, so it is neutral for the last one. We add 60 mL, or 600.60 leaders at 0.50 Mueller. And as you might guess now that we have added mawr ohh than neutral, we should end up with Mawr n a O. H. After the reaction has occurred and we have mhm five times 50.603 moles n a o. H. So because we have added 0.3 moles of any O. H. And we only had 00.2 moles of HCL than subtracting those two. We end up with 0.1 moles, Noh and excess. And if we have extra any ohh, then the solution is going to be basic.

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