00:01
The data given in the problem can be written in the form of a table as x values are minus 6, minus 4, minus 2, 0, 246, 8, 10 and 12.
00:18
And the corresponding y values are 10 .7, 9, 7, 5 .4, 3 .5, 1 .7, minus 0 .1 .7, minus 0 .1, minus 0 .1, minus 1 .8, minus 3 .6 and minus 5 .3.
00:41
Now for this given data, if we first want to create a scatter plot, we will use the graphing device, which is here we will use the ti84 graphing calculator.
00:51
Here go to stat and select the edit option, which is the first option.
00:57
Here we will see two lists.
00:59
Actually we will see multiple lists, but we will use only l1 and l2 here.
01:03
In l1 we will input the x values and in l2 we will input the y values.
01:10
So as you can see we have entered the x and y values here in l1 and l2.
01:16
Now to view this, to view the scatter plot select zoom and the ninth option zoom stat.
01:26
Here we can see the scatter plot.
01:30
Now as we can see these data points follow almost a linear decay path or a linearly decreasing path so we will model this using a linear function so to create the linear model select stat select the right arrow and here we will find the fourth option linear regression so if you select four now before we calculate the model let us store it in as a given function so in the store option press vars go to the right arrow to find yvars select the first option function and select the first function y1 so now that we have selected y1 whatever model is created for this data will be stored as a function y1 and now go to calculate so now the calculator will give us the linear model now any linear equation can be written in in its general form as y equals a x plus b where a the slope of this given model is minus 0 .89 and b the y intercept is 5 .327 so this is the linear model for this given data.
02:49
Now to see the plot of the linear model again press zoom and then the ninth option zoom stat so here along with the scatter plot the calculator will now show us the graph of the linear model...