00:02
Hello and welcome to this video solution of numerate.
00:06
So here it's given that a student wants to determine the coefficient of static friction and kinetic friction between a box and a plank.
00:15
Right.
00:16
She places the box on a plank and gradually raises one end of the plank.
00:24
Right.
00:25
And when the angle of inclination theta is 28 degrees, the box starts to slip.
00:33
Right.
00:33
And it slides a distance of s let's say which is 2 .53 meters down the plank at a time of 3 .92 seconds.
00:45
Based on this you have to calculate the coefficient of frictions.
00:49
Now this is pretty simple.
00:50
So let's say here you have the block.
00:53
Right.
00:55
And here we see that the weight mg is acting downwards.
01:00
Right.
01:01
A component of this weight that is mg sine theta is acting along the incline.
01:09
We have got mg cos theta acting perpendicular to it.
01:14
The normal reaction is perpendicular to the plane itself.
01:20
And here on the opposite side you will be having the frictional force acting.
01:24
Right.
01:25
Now the box is going to slide if mg sine theta just balances the frictional force.
01:33
Right.
01:33
Then it will slide down.
01:36
Now what you have is mg sine theta will be equal to now the frictional force is nothing but mu times the normal reaction.
01:46
Right.
01:47
And this normal reaction is nothing but mg cos theta.
01:54
So clearly mu or this mu is the coefficient of static friction.
01:58
Mu s is equal to tan theta.
02:02
And this tan of this is 28 degrees.
02:06
This gives you the value of static coefficient of static friction as 0 .53.
02:16
So this is the coefficient of static friction you have got.
02:19
Next to calculate the coefficient of kinetic friction you need to consider the motion of the block.
02:26
Right...