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A study of the rate of the reaction represented as 2$A \longrightarrow B$ gave the following data:(a) Determine the average rate of disappearance of A between 0.0 s and 10.0 s, and between 10.0 s and 20.0 s.(b) Estimate the instantaneous rate of disappearance of A at 15.0 s from a graph of time versus [A]. What are the units of this rate?(c) Use the rates found in parts (a) and (b) to determine the average rate of formation of B between 0.00 s and 10.0 s, and the instantaneous rate of formation of B at 15.0 s.

A. 0.255 $\mathrm{mol} \cdot \mathrm{L}^{-1} \cdot \mathrm{s}^{-1}$B. 0.052 $\mathrm{Ms}^{-1}$C. 0.025 $\mathrm{Ms}^{-1}$

Chemistry 102

Chapter 12

Kinetics

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Yeah, for the solution. First we explained that the everything right off the reaction is the rate off concentration off the starting material over a definite period off the time the time gap over which the change in the concentration is measured can be smaller or large. Now we come on, option a off the question. The reaction Toby situated is as polo it is two way. It's got to be now. The average rate off the reaction is the rate off. The change of the concentration off the substance has the given fixed period off the time and is given by Oh, this The average rate is changing concentration divided by changing time. Now that is equal to minus delta concentration divided by Delta be No. The average rate off the disappearance off a between zero second to 12th can be calculated as her We applied formula average red is equal to minus delta a 10 minus delta. Sorry, Have this is equal to minus eight and minus a zero development and minus zero. Here. By solving this, we get the every rate Yes, 3.75 to 10 to the power minus 2 a.m. per second does for the North. The average rate off the disappearance off a between zero second to 10 seconds. 0.0 37 multiple ls Yeah, no for the next. The average rate off the disappearance off a between 10 seconds. 20 seconds. And it can be calculated as using the same form rather off every rate. And we get it 2.55 to 10 to the power minus 2 m per second Now for the next. Thus now for this, the average rate off the disciplines off the A between chancing it 20 seconds is zero point 255 mold and universe as in verse. Now for the part B, the graph off a versus time exploded from the table provided to deter minder instantaneous state off disappearance off a at 15 cents. Second is as follows here. If the this is the graph, this is for a versus time graph, and this is the time this is a and here's the explanation for this attendant is thrown at P equal to 15 seconds, and the slope is calculated as slope equal to Delta 80. Verbal delta and we get the slope is minus 0.26 a. M as universe here this is hence, hence the instantaneous late off the disappearance off a is 0.5 to M s universe the unit off the instantaneous rate or the disappearance off a is M s universe or M s or moral universe as university No at partying. The rate expression for determining the rate off the formation off B is as follows. That is radical tow minus one by two Delta by Delta T is he called two plus Delta bi bi dirty hair. The average read off the disappearance off a between 0 to 10 seconds is 3.75 into 10 to the power minus 2 a.m. per second. Hence the average rate off the formation off be can be calculated at by using this poem in Delta B by Delta Tick is equal to minus one by two Delta A develop identity by objection. And here by putting all the value, we get it 0.188 m per second. Now there's the average rate off the formation of B 0.18 m per second and the instantaneous rate off the disappearance off a is at T is 15 2nd 0.52 am as in words now the instantaneous rate off the formation off be at at equal to 15 2nd days Hair delta be called toe develop a delta equal to minus one by two Delta by identity hereby calculatingly we get the value is 0.25 M s universe now hence the instantaneous rate off the formation of be at 15 cents second is 0.25 cent M s university.

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