00:01
Now, in this problem, we are told that we have a distribution where the mean is 79 and the standard deviation is 73.
00:15
Now, in part a, we want to assume that nothing is known about the shape of the distribution.
00:19
We want to find what percentage is less than 102 units per week.
00:23
So on a, we want to find the probability that x is less than 102 if we know nothing about the distribution.
00:31
Now, if you remember chevy shev's inequality, shevyshev's inequality says that within two standard deviations, it's within 2 sigma, we must have 75 % of the data.
00:48
Within 3, we must have 88 .9.
00:53
And this is regardless of the distribution.
00:57
And so let's draw our distribution here, whatever it may look like.
01:03
We'll have our mean there in the middle, and our mean here is 79.
01:13
Standard deviation is 23, so if we go up 23, and if we go down 23, and we're wanting less than 102, so we're wanting less than the mean plus the standard deviation...