00:01
Let's do part a of the problem.
00:04
We draw the diagram of the situation, identifying the two triangles that are important to finding the solution.
00:12
Well, the submarine is under the surface of water.
00:17
It's 100 meter under the surface of water.
00:21
So the distance of submarine from the surface of the water, let's say this is the surface of the water, right? so it's 100 meter, right? and then here is the building.
00:36
Let's see, this is the building.
00:39
And this is the point.
00:41
Here is the path of light.
00:47
And this angle is phi.
00:50
And here, this angle, this angle is theta one.
00:58
Right? if this angle is theta one, then this angle is also theta one, since both angles are alternate angles and let's say this is angle theta 2 and this distance this distance is 90 meter and here this distance is 210 meter right now uh for part b of the problem uh from the triangle we can see that uh 10 theta 1 is equal to 90 .0 divided by 100, which is equal to 0 .90...