A substance is found to have two phases, $N$ and $S$. In the normal state, the $N$ phase, the magnetization $M$ is negligible. At a fixed temperature $T<T_c$, as the external magnetic field $H$ is lowered below the critical field
$$
H_{\mathrm{c}}(T)=H_0\left[1-\left(\frac{T}{T_{\mathrm{c}}}\right)^2\right],
$$
the normal state undergoes a phase transition to a new state, the $S$ phase. In the $S$ state, it is found that $B=0$ inside the material. The phase diagram is shown below.
(a) Show that the difference in Gibbs free energies (in cgs units) between the two phases at temperature $T \leq T_{\mathrm{c}}$ is given by
$$
G_S(T, H)-G_N(T, H)=\frac{1}{8 \pi}\left[H^2-H_c^2(T)\right] .
$$
(You may express your answer in another system of units. The Gibbs free energy in a magnetic field is given by $G=U-T S-H M$.)
(b) At $H \leq H_0$, compute the latent heat of transition $L$ from the $N$ to the $S$ phase. (Hint: one approach is to consider a "Clausius-Clapeyron" type of analysis.)
(c) At $H=0$, compute the discontinuity in the specific heat as the material transforms from the $N$ to the $S$ phase.
(d) Is the plase transition first or second order at $H=0$ ?
FIGURE CAN'T COPY.