Question
(A): Sulplue (IV) oxide can act as oxidizing as well reducing ageat.(R): In sulphur (IV) oxide sulphur assumes $\mathrm{sp}^{3} \mathrm{~d}$ hybrid state.
Step 1
This is true because Sulphur (IV) oxide is S02, where the oxidation state of Sulphur is +4. Sulphur can increase its oxidation state up to +6 and decrease its oxidation state, which means it can act as both an oxidizing and reducing agent. Show more…
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The oxide of a meral (R) can be reduccd by rhe. meral ( $\mathrm{P}$ ) while meral $(\mathrm{R})$ can rcduce the oxicle of mctal $(\mathrm{Q}) .$ I Icre the dccrcasing ordcr of rhe reacriviry of meral $(\mathrm{P}),(\mathrm{Q})$ and $(\mathrm{R})$ wirh oxygen is (a) $\mathbf{P}>\mathrm{R}>\mathrm{Q}$ (b) $Q>P>R$ (c) $\mathrm{P}>\mathrm{Q}>\mathrm{R}$ (d) $\mathrm{R}>\mathrm{P}>\mathrm{Q}$
In disulphurous acid or pyrosulphurous acid, the oxidation states of sulphur can be (a) $+6$ and $-2$ (b) $+5$ and $+3$ (c) $+6$ and 0 (d) $+5$ and $-2$
Like sulphur, oxygen does not show $+4$ and $+6$ oxidation states. The reason is (1) That oxygen is a gas while sulphur is a solid (2) That oxygen has high ionisation enthalpies in comparison to sulphur (3) That oxygen has high electron affinity in comparison to sulphur (4) That oxygen has no $d$-orbitals in its valence shell
p-Block Group 16 Elements The Oxygen Family
Linked Comprehension Type
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