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A supernova explosion of a $2.00 \times 10^{31} \mathrm{kg}$ star produces $1.00 \times 10^{44} \mathrm{kg}$ of energy. (a) How many kilograms of mass are converted to energy in the explosion? (b) What is the ratio $\Delta \mathrm{m} / \mathrm{m}$ of mass destroyed to the original mass of the star?

(a) $1.11 \times 10^{27} \mathrm{kg},$ (b) $1.80 \times 10^{4}$

Physics 103

Chapter 28

Special Relativity

Relativity

Cornell University

Simon Fraser University

Hope College

University of Winnipeg

Lectures

02:35

In physics, the theory of …

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03:14

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03:18

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01:41

04:34

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barking. Uh, the energy produces in the explosion. Uh, e it's equal to 1.0 Multiply by 10 to the power 44 jewels. This is the energy produced in explosion on the speed of light. C equals 3.0 Multiply by 10 to the power eight meter per second, hence the equivalent amount of mass. Uh, Dr M is equal to Edie. Binding by C square. Uh, equal into mass is equal to well, he is 1.0 Multiply by 10 to the dollar. 44 divided by C square. Well, see is 3.0 multiply. We tend to the power eat square and this gives us 1.11 multiplied by 10 to the power 27 kilograms. So, uh, 1.11 multiplied attend to borrow 27 kilogram off Marce eyes Can working into energy. Let's do part B. Well, The reason most of the star M is equal to 2.0 multiplied by 10 to the power 31 kilogram, 31 kilogram. On the ratio is Delta M, divided by AM Well, Delta am is 1.11 multiplied by 10 to the dollar. 27. Divided by well, the original mass of the star is 2.0 Multiply by 10 to the power 31 and dividing the two numbers. We have a 1.8 serial multiply by 10 to the power four. Hence the ratio must destroy to the regional. Moss of the Star is one point. It's it'll multiply. I tend to be power for.

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