Question
A system is executing S.H.M. The potential energy of the system for displacement $\mathrm{x}$ is $\mathrm{E}_{1}$ and for a displacement of $\mathrm{y}$, the potential energy of the system is $E_{2}$. The potential energy for a displacement of $(x+j)$ is $\ldots \ldots \ldots$(A) $E_{1}+E_{2}$(B) $\left.\sqrt{(} \mathrm{E}_{1}^{2}+\mathrm{E}_{2}{ }^{2}\right)$(C) $\mathrm{E}_{1}+\mathrm{E}_{2}+2 \sqrt{\mathrm{E}}_{1} \mathrm{E}_{2}$(D) $\sqrt{E}_{1} E_{2}$
Step 1
Step 1: The potential energy of a system executing simple harmonic motion is given by the formula $E = \frac{1}{2}m\omega^2x^2$, where $m$ is the mass of the system, $\omega$ is the angular frequency and $x$ is the displacement. Show more…
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Section B
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