Question
A system releases $125 \mathrm{~kJ}$ of heat while $104 \mathrm{~kJ}$ of work is doneon it. Calculate $\Delta E$.
Step 1
First, we need to recall the first law of thermodynamics, which states that the change in internal energy (∆E) of a system is equal to the heat (Q) added to the system minus the work (W) done by the system: ∆E = Q - W In this problem, we are given that the system Show more…
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