Question
A system with nondegenerate energy levels has three energy states: a ground state at $E=0$ and excited states at energies of $0.045 \mathrm{eV}$ and $0.135 \mathrm{eV}$. At a temperature of $650 \mathrm{~K},$ find the relative numbers of particles in the three states.
Step 1
The Boltzmann constant is $8.617 \times 10^{-5} \, eV/K$ and the temperature is $650 \, K$. Therefore, $kT = 8.617 \times 10^{-5} \, eV/K \times 650 \, K = 0.056 \, eV$. Show more…
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A system with nondegenerate energy levels has three energy states: a ground state at $E=0$ and excited states at energies of $0.045 \mathrm{eV}$ and $0.135 \mathrm{eV} .$ At a temperature of $650 \mathrm{K},$ find the relative numbers of particles in the three states.
A system consists of $N$ particles that can occupy two energy levels: a nondegenerate ground state and a three-fold degenerate excited state, which is at an energy of $0.25 \mathrm{eV}$ above the ground state. At a temperature of $960 \mathrm{~K}$, find the number of particles in the ground state and in the excited state.
A system consists of $N$ particles that can occupy two cnergy levels: a nondegenerate ground state and a threefold degenerate excited state, which is at an energy of $0.25 \mathrm{eV}$ above the ground state. At a temperature of $960 \mathrm{K},$ find the number of particles in the ground state and in the excited state.
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