00:01
All right, so in this question we're given ozenolysis products and asked to determine what is the likely reactant.
00:07
So the first thing we have is this guy right here, like that.
00:19
And we're going to draw retro synthetic errors, kind of this double -ended error, to show that we're working backwards.
00:25
So obviously we've got two carboneals, meaning there was probably two kind of available sites for cleavage.
00:32
But we know we only have one product.
00:34
So this probably was some sort of a range structure.
00:37
Now since the carboneals are more than likely the site of cleavage, we can say this is one, two, three, four, five, six, right? so that obviously kind of shows that we have some sort of six -membered ring like this, right? where we just have an alkyne right here.
00:56
Notice though at carbon one, we have a methyl substituent, meaning we probably have a methyl kind of just off the edge like that.
01:03
All right, b is just a little more complicated where we've got several, products.
01:10
The first being a one, two, three, four, five member thing.
01:14
So we have something that looks like this.
01:26
No, we also have two other products.
01:31
The first just being something looks like this.
01:35
And the third being something that looks like this.
01:42
Okay.
01:43
So we can probably expect that this is going to be a very, very, very, long carbon chain with multiple double bonds.
01:54
So one way to do this is first just count up all the carbons and label all of the chains...