00:01
So this problem starts by writing the balanced equation for the combustion of propane to form liquid water and gaseous water.
00:11
And so we'll start with gaseous water.
00:15
So c3h8 gas plus 502 gas, forms 4h2 gas, plus 3 co2 gas.
00:25
And then we'll write the same thing again.
00:30
But with the only change being liquid water.
00:39
So then moving into problem b, we want to find the delta h of reaction of each of these.
00:46
And so since it gives the delta h of combustion for this first reaction, being the hv, as negative 2219 kilojoules per mole, we know that's our answer.
00:59
And as far as the delta h reaction for the one with liquid water, we just take our 2219 kilojoules per mole and add the heat of vaporization of water times the number of moles of water.
01:14
And this is explained in the problem...