Question
(a) The ionization energy of sodium is $5.14 \mathrm{eV}$. What is the effective charge seen by the outer electron? $(b)$ If the $3 s$ electron of a sodium atom is moved to the $4 f$ state, the measured binding energy is $0.85 \mathrm{eV}$. What is the effective charge seen by an electron in this state?
Step 1
14 eV. This is the energy required to remove the outermost electron from a sodium atom. We can denote this energy as $E_{3s}$, which is the energy of the 3s electron in the sodium atom. Therefore, we have $E_{3s} = -5.14 \, \text{eV}$. Show more…
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(a) The energy of an electron in the 4 state of sodium is $-1.947$ eV. What is the effective net charge of the nucleus "seen" by this electron? On the average, how many electrons screen the nucleus? (b) For an outer electron in the 4$p$ state of potassium, on the average 17.2 inner electrons screen the nucleus. (i) What is the effective net charge of the nucleus "seen" by this outer electron? (ii) What is the energy of this outer electron?
Estimate the effective nuclear charge felt by the 3s electron in the sodium atom, if the ionization energy is 5.14 eV.
If the $3 s$ electron in sodium did not penetrate the inner core, its energy would be $-13.6 \mathrm{eV} / 3^{2}=-1.51 \mathrm{eV} .$ Because it does penetrate, it sees a higher effective $Z$ and its energy is lower. Use the measured ionization potential of $5.14 \mathrm{~V}$ to calculate $Z_{\text {eff }}$ for the $3 s$ electron in sodium.
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