00:01
Okay, so in this problem, we have an hydrogen atom and we know that his probability distribution function has a peak, one peak, with the radius of 0 .476 nanometers.
00:24
Therefore, this is 10 to the negative 9 meters.
00:29
Okay, first of all, in this problem, we want to know what is the spectroscopy notation of this state.
00:41
Therefore, we just want to know what is the value of n and the value of l.
00:47
Okay, and how we go into discover this? well, for this, we must go to the book, and we're going to find that the radius, maximum, is defined r equals n square, this is an n, that multiplies a, where a is the bore radius.
01:17
If you don't remember the numerical value of bar radius, well, this is, this can define in the book also, and we have the value of 5 .29.
01:35
Times 10 to the negative 11 meters.
01:40
Okay? therefore since we know our radius and we want to describe the spectroscopy, well we just need to solve this equation for n.
01:53
Therefore n square is going to be r divided by a.
01:58
Therefore this is 0 .476 times 10 to the negative 9, divided by a, by 5 .29 times 10 to the minus 11 and this gives us something close let's put here an approximated value of 9 since this is 9 well n equals 3 but what is the value of l well since n equals 3 l could only be l could only be 0, 1 or 2.
02:48
Since we are in a lower peak, we can presume that we actually are in this state n equals 3, l equals 0...