A thin lens has focal length $\mathrm{f}$, and its aperture has diameter
d. It forms an image of intensity I. Now, the central part of the aperture upto diameter $(\mathrm{d} / 2)$ is blocked by an opaque paper. The focal length and image intensity will change to $\ldots$
(A) $\mathrm{f}$ and $(3 \mathrm{I} / 4)$
(B) $(3 \mathrm{f} / 4)$ and $(\mathrm{I} / 2)$
(C) $\mathrm{f}$ and $(\mathrm{I} / 4)$
(D) $(\mathrm{f} / 2)$ and $(\mathrm{I} / 2)$